Question

800. Similar RGB Color

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Description

The red-green-blue color "#AABBCC" can be written as "#ABC" in shorthand.

• For example, "#15c" is shorthand for the color "#1155cc".

The similarity between the two colors "#ABCDEF" and "#UVWXYZ" is -(AB - UV)2 - (CD - WX)2 - (EF - YZ)2.

Given a string color that follows the format "#ABCDEF", return a string represents the color that is most similar to the given color and has a shorthand (i.e., it can be represented as some "#XYZ").

Any answer which has the same highest similarity as the best answer will be accepted.

 

Example 1:

Input: color = "#09f166"
Output: "#11ee66"
Explanation: 
The similarity is -(0x09 - 0x11)2 -(0xf1 - 0xee)2 - (0x66 - 0x66)2 = -64 -9 -0 = -73.
This is the highest among any shorthand color.

Example 2:

Input: color = "#4e3fe1"
Output: "#5544dd"

 

Constraints:

• color.length == 7
• color[0] == '#'
• color[i] is either digit or character in the range ['a', 'f'] for i > 0.

Solutions

Solution 1

class Solution:
  def similarRGB(self, color: str) -> str:
    def f(x):
      y, z = divmod(int(x, 16), 17)
      if z > 8:
        y += 1
      return '{:02x}'.format(17 * y)

    a, b, c = color[1:3], color[3:5], color[5:7]
    return f'#{f(a)}{f(b)}{f(c)}'

class Solution {
  public String similarRGB(String color) {
    String a = color.substring(1, 3), b = color.substring(3, 5), c = color.substring(5, 7);
    return "#" + f(a) + f(b) + f(c);
  }

  private String f(String x) {
    int q = Integer.parseInt(x, 16);
    q = q / 17 + (q % 17 > 8 ? 1 : 0);
    return String.format("%02x", 17 * q);
  }
}

func similarRGB(color string) string {
  f := func(x string) string {
    q, _ := strconv.ParseInt(x, 16, 64)
    if q%17 > 8 {
      q = q/17 + 1
    } else {
      q = q / 17
    }
    return fmt.Sprintf("%02x", 17*q)

  }
  a, b, c := color[1:3], color[3:5], color[5:7]
  return "#" + f(a) + f(b) + f(c)
}