Question

延时执行某函数，且只会执行一次。

代码

function delay(fn = () => { }, delay = 5000, context = null) {
  let ticket = null;
  let runned = false;
  return {
    run(...args) {
      return new Promise((resolve, reject) => {
        if (runned === true) {
          return;
        }
        runned = true;
        ticket = setTimeout(async () => {
          try {
            const res = await fn.apply(context, args);
            resolve(res);
          } catch (err) {
            reject(err)
          }
        }, delay)
      })
    },
    cancel: () => {
      clearTimeout(ticket);
    }
  }
}

示例

delay(function () {
  console.log("你们好");
}).run();

const { run, cancel } = delay(function (name) {
  console.log("你好：", name);
});

run("吉他");
run("吉他");

// 你们好
// 你好： 吉他