返回介绍

solution / 0000-0099 / 0012.Integer to Roman / README_EN

发布于 2024-06-17 01:04:40 字数 6406 浏览 0 评论 0 收藏 0

12. Integer to Roman

中文文档

Description

Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M.

Symbol     Value
I       1
V       5
X       10
L       50
C       100
D       500
M       1000

For example, 2 is written as II in Roman numeral, just two one's added together. 12 is written as XII, which is simply X + II. The number 27 is written as XXVII, which is XX + V + II.

Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII. Instead, the number four is written as IV. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX. There are six instances where subtraction is used:

  • I can be placed before V (5) and X (10) to make 4 and 9. 
  • X can be placed before L (50) and C (100) to make 40 and 90. 
  • C can be placed before D (500) and M (1000) to make 400 and 900.

Given an integer, convert it to a roman numeral.

 

Example 1:

Input: num = 3
Output: "III"
Explanation: 3 is represented as 3 ones.

Example 2:

Input: num = 58
Output: "LVIII"
Explanation: L = 50, V = 5, III = 3.

Example 3:

Input: num = 1994
Output: "MCMXCIV"
Explanation: M = 1000, CM = 900, XC = 90 and IV = 4.

 

Constraints:

  • 1 <= num <= 3999

Solutions

Solution 1: Greedy

We can first list all possible symbols $cs$ and their corresponding values $vs$, then enumerate each value $vs[i]$ from large to small. Each time, we use as many symbols $cs[i]$ corresponding to this value as possible, until the number $num$ becomes $0$.

The time complexity is $O(m)$, and the space complexity is $O(m)$. Here, $m$ is the number of symbols.

class Solution:
  def intToRoman(self, num: int) -> str:
    cs = ('M', 'CM', 'D', 'CD', 'C', 'XC', 'L', 'XL', 'X', 'IX', 'V', 'IV', 'I')
    vs = (1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1)
    ans = []
    for c, v in zip(cs, vs):
      while num >= v:
        num -= v
        ans.append(c)
    return ''.join(ans)
class Solution {
  public String intToRoman(int num) {
    List<String> cs
      = List.of("M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I");
    List<Integer> vs = List.of(1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1);
    StringBuilder ans = new StringBuilder();
    for (int i = 0, n = cs.size(); i < n; ++i) {
      while (num >= vs.get(i)) {
        num -= vs.get(i);
        ans.append(cs.get(i));
      }
    }
    return ans.toString();
  }
}
class Solution {
public:
  string intToRoman(int num) {
    vector<string> cs = {"M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"};
    vector<int> vs = {1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1};
    string ans;
    for (int i = 0; i < cs.size(); ++i) {
      while (num >= vs[i]) {
        num -= vs[i];
        ans += cs[i];
      }
    }
    return ans;
  }
};
func intToRoman(num int) string {
  cs := []string{"M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"}
  vs := []int{1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1}
  ans := &strings.Builder{}
  for i, v := range vs {
    for num >= v {
      num -= v
      ans.WriteString(cs[i])
    }
  }
  return ans.String()
}
function intToRoman(num: number): string {
  const cs: string[] = ['M', 'CM', 'D', 'CD', 'C', 'XC', 'L', 'XL', 'X', 'IX', 'V', 'IV', 'I'];
  const vs: number[] = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1];
  const ans: string[] = [];
  for (let i = 0; i < vs.length; ++i) {
    while (num >= vs[i]) {
      num -= vs[i];
      ans.push(cs[i]);
    }
  }
  return ans.join('');
}
public class Solution {
  public string IntToRoman(int num) {
    List<string> cs = new List<string>{"M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"};
    List<int> vs = new List<int>{1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1};
    StringBuilder ans = new StringBuilder();
    for (int i = 0; i < cs.Count; i++) {
      while (num >= vs[i]) {
        ans.Append(cs[i]);
        num -= vs[i];
      }
    }
    return ans.ToString();
  }
}
class Solution {
  /**
   * @param int $num
   * @return string
   */

  function intToRoman($num) {
    $values = [
      'M' => 1000,
      'CM' => 900,
      'D' => 500,
      'CD' => 400,
      'C' => 100,
      'XC' => 90,
      'L' => 50,
      'XL' => 40,
      'X' => 10,
      'IX' => 9,
      'V' => 5,
      'IV' => 4,
      'I' => 1,
    ];

    $result = '';

    foreach ($values as $roman => $value) {
      while ($num >= $value) {
        $result .= $roman;
        $num -= $value;
      }
    }

    return $result;
  }
}

如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

扫码二维码加入Web技术交流群

发布评论

需要 登录 才能够评论, 你可以免费 注册 一个本站的账号。
列表为空,暂无数据
    我们使用 Cookies 和其他技术来定制您的体验包括您的登录状态等。通过阅读我们的 隐私政策 了解更多相关信息。 单击 接受 或继续使用网站,即表示您同意使用 Cookies 和您的相关数据。
    原文