Question

2628. JSON Deep Equal

中文文档

Description

Given two values o1 and o2, return a boolean value indicating whether two values, o1 and o2, are deeply equal.

For two values to be deeply equal, the following conditions must be met:

• If both values are primitive types, they are deeply equal if they pass the === equality check.

• If both values are arrays, they are deeply equal if they have the same elements in the same order, and each element is also deeply equal according to these conditions.

• If both values are objects, they are deeply equal if they have the same keys, and the associated values for each key are also deeply equal according to these conditions.

You may assume both values are the output of JSON.parse. In other words, they are valid JSON.

Please solve it without using lodash's _.isEqual() function

 

Example 1:

Input: o1 = {"x":1,"y":2}, o2 = {"x":1,"y":2}
Output: true
Explanation: The keys and values match exactly.

Example 2:

Input: o1 = {"y":2,"x":1}, o2 = {"x":1,"y":2}
Output: true
Explanation: Although the keys are in a different order, they still match exactly.

Example 3:

Input: o1 = {"x":null,"L":[1,2,3]}, o2 = {"x":null,"L":["1","2","3"]}
Output: false
Explanation: The array of numbers is different from the array of strings.

Example 4:

Input: o1 = true, o2 = false
Output: false
Explanation: true !== false

 

Constraints:

• 1 <= JSON.stringify(o1).length <= 105
• 1 <= JSON.stringify(o2).length <= 105
• maxNestingDepth <= 1000

Solutions

Solution 1

function areDeeplyEqual(o1: any, o2: any): boolean {
  if (o1 === null || typeof o1 !== 'object') {
    return o1 === o2;
  }
  if (typeof o1 !== typeof o2) {
    return false;
  }
  if (Array.isArray(o1) !== Array.isArray(o2)) {
    return false;
  }
  if (Array.isArray(o1)) {
    if (o1.length !== o2.length) {
      return false;
    }
    for (let i = 0; i < o1.length; i++) {
      if (!areDeeplyEqual(o1[i], o2[i])) {
        return false;
      }
    }
    return true;
  } else {
    const keys1 = Object.keys(o1);
    const keys2 = Object.keys(o2);
    if (keys1.length !== keys2.length) {
      return false;
    }
    for (const key of keys1) {
      if (!areDeeplyEqual(o1[key], o2[key])) {
        return false;
      }
    }
    return true;
  }
}