Question

1507. Reformat Date

中文文档

Description

Given a date string in the form Day Month Year, where:

• Day is in the set {"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}.
• Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}.
• Year is in the range [1900, 2100].

Convert the date string to the format YYYY-MM-DD, where:

• YYYY denotes the 4 digit year.
• MM denotes the 2 digit month.
• DD denotes the 2 digit day.

 

Example 1:

Input: date = "20th Oct 2052"
Output: "2052-10-20"

Example 2:

Input: date = "6th Jun 1933"
Output: "1933-06-06"

Example 3:

Input: date = "26th May 1960"
Output: "1960-05-26"

 

Constraints:

• The given dates are guaranteed to be valid, so no error handling is necessary.

Solutions

Solution 1

class Solution:
  def reformatDate(self, date: str) -> str:
    s = date.split()
    s.reverse()
    months = " JanFebMarAprMayJunJulAugSepOctNovDec"
    s[1] = str(months.index(s[1]) // 3 + 1).zfill(2)
    s[2] = s[2][:-2].zfill(2)
    return "-".join(s)

class Solution {
  public String reformatDate(String date) {
    var s = date.split(" ");
    String months = " JanFebMarAprMayJunJulAugSepOctNovDec";
    int day = Integer.parseInt(s[0].substring(0, s[0].length() - 2));
    int month = months.indexOf(s[1]) / 3 + 1;
    return String.format("%s-%02d-%02d", s[2], month, day);
  }
}

class Solution {
public:
  string reformatDate(string date) {
    string months = " JanFebMarAprMayJunJulAugSepOctNovDec";
    stringstream ss(date);
    string year, month, t;
    int day;
    ss >> day >> t >> month >> year;
    month = to_string(months.find(month) / 3 + 1);
    return year + "-" + (month.size() == 1 ? "0" + month : month) + "-" + (day > 9 ? "" : "0") + to_string(day);
  }
};

func reformatDate(date string) string {
  s := strings.Split(date, " ")
  day, _ := strconv.Atoi(s[0][:len(s[0])-2])
  months := " JanFebMarAprMayJunJulAugSepOctNovDec"
  month := strings.Index(months, s[1])/3 + 1
  year, _ := strconv.Atoi(s[2])
  return fmt.Sprintf("%d-%02d-%02d", year, month, day)
}

function reformatDate(date: string): string {
  const s = date.split(' ');
  const months = ' JanFebMarAprMayJunJulAugSepOctNovDec';
  const day = parseInt(s[0].substring(0, s[0].length - 2));
  const month = Math.floor(months.indexOf(s[1]) / 3) + 1;
  return `${s[2]}-${month.toString().padStart(2, '0')}-${day.toString().padStart(2, '0')}`;
}

class Solution {
  /**
   * @param String $date
   * @return String
   */
  function reformatDate($date) {
    $arr = explode(' ', $date);
    $months = [
      'Jan' => '01',
      'Feb' => '02',
      'Mar' => '03',
      'Apr' => '04',
      'May' => '05',
      'Jun' => '06',
      'Jul' => '07',
      'Aug' => '08',
      'Sep' => '09',
      'Oct' => '10',
      'Nov' => '11',
      'Dec' => '12',
    ];
    $year = $arr[2];
    $month = $months[$arr[1]];
    $day = intval($arr[0]);
    if ($day > 0 && $day < 10) {
      $day = '0' . $day;
    }
    return $year . '-' . $month . '-' . $day;
  }
}