返回介绍

solution / 0100-0199 / 0166.Fraction to Recurring Decimal / README_EN

发布于 2024-06-17 01:04:03 字数 5863 浏览 0 评论 0 收藏 0

166. Fraction to Recurring Decimal

中文文档

Description

Given two integers representing the numerator and denominator of a fraction, return _the fraction in string format_.

If the fractional part is repeating, enclose the repeating part in parentheses.

If multiple answers are possible, return any of them.

It is guaranteed that the length of the answer string is less than 104 for all the given inputs.

 

Example 1:

Input: numerator = 1, denominator = 2
Output: "0.5"

Example 2:

Input: numerator = 2, denominator = 1
Output: "2"

Example 3:

Input: numerator = 4, denominator = 333
Output: "0.(012)"

 

Constraints:

  • -231 <= numerator, denominator <= 231 - 1
  • denominator != 0

Solutions

Solution 1

class Solution:
  def fractionToDecimal(self, numerator: int, denominator: int) -> str:
    if numerator == 0:
      return '0'
    res = []
    neg = (numerator > 0) ^ (denominator > 0)
    if neg:
      res.append('-')
    num, d = abs(numerator), abs(denominator)
    res.append(str(num // d))
    num %= d
    if num == 0:
      return ''.join(res)
    res.append('.')
    mp = {}
    while num != 0:
      mp[num] = len(res)
      num *= 10
      res.append(str(num // d))
      num %= d
      if num in mp:
        idx = mp[num]
        res.insert(idx, '(')
        res.append(')')
        break
    return ''.join(res)
class Solution {
  public String fractionToDecimal(int numerator, int denominator) {
    if (numerator == 0) {
      return "0";
    }
    StringBuilder sb = new StringBuilder();
    boolean neg = (numerator > 0) ^ (denominator > 0);
    sb.append(neg ? "-" : "");
    long num = Math.abs((long) numerator);
    long d = Math.abs((long) denominator);
    sb.append(num / d);
    num %= d;
    if (num == 0) {
      return sb.toString();
    }
    sb.append(".");
    Map<Long, Integer> mp = new HashMap<>();
    while (num != 0) {
      mp.put(num, sb.length());
      num *= 10;
      sb.append(num / d);
      num %= d;
      if (mp.containsKey(num)) {
        int idx = mp.get(num);
        sb.insert(idx, "(");
        sb.append(")");
        break;
      }
    }
    return sb.toString();
  }
}
using LL = long long;

class Solution {
public:
  string fractionToDecimal(int numerator, int denominator) {
    if (numerator == 0) return "0";
    string res = "";
    bool neg = (numerator > 0) ^ (denominator > 0);
    if (neg) res += "-";
    LL num = abs(numerator);
    LL d = abs(denominator);
    res += to_string(num / d);
    num %= d;
    if (num == 0) return res;
    res += ".";
    unordered_map<LL, int> mp;
    while (num) {
      mp[num] = res.size();
      num *= 10;
      res += to_string(num / d);
      num %= d;
      if (mp.count(num)) {
        int idx = mp[num];
        res.insert(idx, "(");
        res += ")";
        break;
      }
    }
    return res;
  }
};
func fractionToDecimal(numerator int, denominator int) string {
  if numerator == 0 {
    return "0"
  }
  res := []byte{}
  neg := numerator*denominator < 0
  if neg {
    res = append(res, '-')
  }
  num := abs(numerator)
  d := abs(denominator)
  res = append(res, strconv.Itoa(num/d)...)
  num %= d
  if num == 0 {
    return string(res)
  }
  mp := make(map[int]int)
  res = append(res, '.')
  for num != 0 {
    mp[num] = len(res)
    num *= 10
    res = append(res, strconv.Itoa(num/d)...)
    num %= d
    if mp[num] > 0 {
      idx := mp[num]
      res = append(res[:idx], append([]byte{'('}, res[idx:]...)...)
      res = append(res, ')')
      break
    }
  }

  return string(res)
}

func abs(x int) int {
  if x < 0 {
    return -x
  }
  return x
}
// https://leetcode.com/problems/fraction-to-recurring-decimal/

using System.Collections.Generic;
using System.Text;

public partial class Solution
{
  public string FractionToDecimal(int numerator, int denominator)
  {
    var n = (long)numerator;
    var d = (long)denominator;
    var sb = new StringBuilder();
    if (n < 0)
    {
      n = -n;
      if (d < 0)
      {
        d = -d;
      }
      else
      {
        sb.Append('-');
      }
    }
    else if (n > 0 && d < 0)
    {
      d = -d;
      sb.Append('-');
    }

    sb.Append(n / d);
    n = n % d;
    if (n != 0)
    {
      sb.Append('.');
      var dict = new Dictionary<long, int>();
      while (n != 0)
      {
        int index;
        if (dict.TryGetValue(n, out index))
        {
          sb.Insert(index, '(');
          sb.Append(')');
          break;
        }
        else
        {
          dict.Add(n, sb.Length);
          n *= 10;
          sb.Append(n / d);
          n %= d;
        }
      }
    }
    return sb.ToString();
  }
}

如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

扫码二维码加入Web技术交流群

发布评论

需要 登录 才能够评论, 你可以免费 注册 一个本站的账号。
列表为空,暂无数据
    我们使用 Cookies 和其他技术来定制您的体验包括您的登录状态等。通过阅读我们的 隐私政策 了解更多相关信息。 单击 接受 或继续使用网站,即表示您同意使用 Cookies 和您的相关数据。
    原文