Question

2347. Best Poker Hand

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Description

You are given an integer array ranks and a character array suits. You have 5 cards where the ith card has a rank of ranks[i] and a suit of suits[i].

The following are the types of poker hands you can make from best to worst:

1. "Flush": Five cards of the same suit.
2. "Three of a Kind": Three cards of the same rank.
3. "Pair": Two cards of the same rank.
4. "High Card": Any single card.

Return _a string representing the best type of poker hand you can make with the given cards._

Note that the return values are case-sensitive.

 

Example 1:

Input: ranks = [13,2,3,1,9], suits = ["a","a","a","a","a"]
Output: "Flush"
Explanation: The hand with all the cards consists of 5 cards with the same suit, so we have a "Flush".

Example 2:

Input: ranks = [4,4,2,4,4], suits = ["d","a","a","b","c"]
Output: "Three of a Kind"
Explanation: The hand with the first, second, and fourth card consists of 3 cards with the same rank, so we have a "Three of a Kind".
Note that we could also make a "Pair" hand but "Three of a Kind" is a better hand.
Also note that other cards could be used to make the "Three of a Kind" hand.

Example 3:

Input: ranks = [10,10,2,12,9], suits = ["a","b","c","a","d"]
Output: "Pair"
Explanation: The hand with the first and second card consists of 2 cards with the same rank, so we have a "Pair".
Note that we cannot make a "Flush" or a "Three of a Kind".

 

Constraints:

• ranks.length == suits.length == 5
• 1 <= ranks[i] <= 13
• 'a' <= suits[i] <= 'd'
• No two cards have the same rank and suit.

Solutions

Solution 1

class Solution:
  def bestHand(self, ranks: List[int], suits: List[str]) -> str:
    # if len(set(suits)) == 1:
    if all(a == b for a, b in pairwise(suits)):
      return 'Flush'
    cnt = Counter(ranks)
    if any(v >= 3 for v in cnt.values()):
      return 'Three of a Kind'
    if any(v == 2 for v in cnt.values()):
      return 'Pair'
    return 'High Card'

class Solution {
  public String bestHand(int[] ranks, char[] suits) {
    boolean flush = true;
    for (int i = 1; i < 5 && flush; ++i) {
      flush = suits[i] == suits[i - 1];
    }
    if (flush) {
      return "Flush";
    }
    int[] cnt = new int[14];
    boolean pair = false;
    for (int x : ranks) {
      if (++cnt[x] == 3) {
        return "Three of a Kind";
      }
      pair = pair || cnt[x] == 2;
    }
    return pair ? "Pair" : "High Card";
  }
}

class Solution {
public:
  string bestHand(vector<int>& ranks, vector<char>& suits) {
    bool flush = true;
    for (int i = 1; i < 5 && flush; ++i) {
      flush = suits[i] == suits[i - 1];
    }
    if (flush) {
      return "Flush";
    }
    int cnt[14]{};
    bool pair = false;
    for (int& x : ranks) {
      if (++cnt[x] == 3) {
        return "Three of a Kind";
      }
      pair |= cnt[x] == 2;
    }
    return pair ? "Pair" : "High Card";
  }
};

func bestHand(ranks []int, suits []byte) string {
  flush := true
  for i := 1; i < 5 && flush; i++ {
    flush = suits[i] == suits[i-1]
  }
  if flush {
    return "Flush"
  }
  cnt := [14]int{}
  pair := false
  for _, x := range ranks {
    cnt[x]++
    if cnt[x] == 3 {
      return "Three of a Kind"
    }
    pair = pair || cnt[x] == 2
  }
  if pair {
    return "Pair"
  }
  return "High Card"
}

function bestHand(ranks: number[], suits: string[]): string {
  if (suits.every(v => v === suits[0])) {
    return 'Flush';
  }
  const count = new Array(14).fill(0);
  let isPair = false;
  for (const v of ranks) {
    if (++count[v] === 3) {
      return 'Three of a Kind';
    }
    isPair = isPair || count[v] === 2;
  }
  if (isPair) {
    return 'Pair';
  }
  return 'High Card';
}

impl Solution {
  pub fn best_hand(ranks: Vec<i32>, suits: Vec<char>) -> String {
    if suits.iter().all(|v| *v == suits[0]) {
      return "Flush".to_string();
    }
    let mut count = [0; 14];
    let mut is_pair = false;
    for &v in ranks.iter() {
      let i = v as usize;
      count[i] += 1;
      if count[i] == 3 {
        return "Three of a Kind".to_string();
      }
      is_pair = is_pair || count[i] == 2;
    }
    (if is_pair { "Pair" } else { "High Card" }).to_string()
  }
}

char* bestHand(int* ranks, int ranksSize, char* suits, int suitsSize) {
  bool isFlush = true;
  for (int i = 1; i < suitsSize; i++) {
    if (suits[0] != suits[i]) {
      isFlush = false;
      break;
    }
  }
  if (isFlush) {
    return "Flush";
  }
  int count[14] = {0};
  bool isPair = false;
  for (int i = 0; i < ranksSize; i++) {
    if (++count[ranks[i]] == 3) {
      return "Three of a Kind";
    }
    isPair = isPair || count[ranks[i]] == 2;
  }
  if (isPair) {
    return "Pair";
  }
  return "High Card";
}