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lcof2 / 剑指 Offer II 043. 往完全二叉树添加节点 / README

发布于 2024-06-17 01:04:41 字数 7630 浏览 0 评论 0 收藏 0

剑指 Offer II 043. 往完全二叉树添加节点

题目描述

完全二叉树是每一层(除最后一层外)都是完全填充(即,节点数达到最大,第 n 层有 2n-1 个节点)的,并且所有的节点都尽可能地集中在左侧。

设计一个用完全二叉树初始化的数据结构 CBTInserter,它支持以下几种操作:

  • CBTInserter(TreeNode root) 使用根节点为 root 的给定树初始化该数据结构;
  • CBTInserter.insert(int v)  向树中插入一个新节点,节点类型为 TreeNode,值为 v 。使树保持完全二叉树的状态,并返回插入的新节点的父节点的值
  • CBTInserter.get_root() 将返回树的根节点。

 

    示例 1:

    输入:inputs = ["CBTInserter","insert","get_root"], inputs = [[[1]],[2],[]]
    输出:[null,1,[1,2]]
    

    示例 2:

    输入:inputs = ["CBTInserter","insert","insert","get_root"], inputs = [[[1,2,3,4,5,6]],[7],[8],[]]
    输出:[null,3,4,[1,2,3,4,5,6,7,8]]
    

     

    提示:

    • 最初给定的树是完全二叉树,且包含 1 到 1000 个节点。
    • 每个测试用例最多调用 CBTInserter.insert  操作 10000 次。
    • 给定节点或插入节点的每个值都在 0 到 5000 之间。

     

    注意:本题与主站 919 题相同: https://leetcode.cn/problems/complete-binary-tree-inserter/

    解法

    方法一

    # Definition for a binary tree node.
    # class TreeNode:
    #   def __init__(self, val=0, left=None, right=None):
    #     self.val = val
    #     self.left = left
    #     self.right = right
    class CBTInserter:
      def __init__(self, root: TreeNode):
        self.tree = []
        q = deque([root])
        while q:
          for _ in range(len(q)):
            node = q.popleft()
            self.tree.append(node)
            if node.left:
              q.append(node.left)
            if node.right:
              q.append(node.right)
    
      def insert(self, v: int) -> int:
        pid = (len(self.tree) - 1) >> 1
        node = TreeNode(v)
        self.tree.append(node)
        p = self.tree[pid]
        if p.left is None:
          p.left = node
        else:
          p.right = node
        return p.val
    
      def get_root(self) -> TreeNode:
        return self.tree[0]
    
    
    # Your CBTInserter object will be instantiated and called as such:
    # obj = CBTInserter(root)
    # param_1 = obj.insert(v)
    # param_2 = obj.get_root()
    
    /**
     * Definition for a binary tree node.
     * public class TreeNode {
     *   int val;
     *   TreeNode left;
     *   TreeNode right;
     *   TreeNode() {}
     *   TreeNode(int val) { this.val = val; }
     *   TreeNode(int val, TreeNode left, TreeNode right) {
     *     this.val = val;
     *     this.left = left;
     *     this.right = right;
     *   }
     * }
     */
    class CBTInserter {
      private List<TreeNode> tree;
    
      public CBTInserter(TreeNode root) {
        tree = new ArrayList<>();
        Deque<TreeNode> q = new ArrayDeque<>();
        q.offer(root);
        while (!q.isEmpty()) {
          TreeNode node = q.pollFirst();
          tree.add(node);
          if (node.left != null) {
            q.offer(node.left);
          }
          if (node.right != null) {
            q.offer(node.right);
          }
        }
      }
    
      public int insert(int v) {
        int pid = (tree.size() - 1) >> 1;
        TreeNode node = new TreeNode(v);
        tree.add(node);
        TreeNode p = tree.get(pid);
        if (p.left == null) {
          p.left = node;
        } else {
          p.right = node;
        }
        return p.val;
      }
    
      public TreeNode get_root() {
        return tree.get(0);
      }
    }
    
    /**
     * Your CBTInserter object will be instantiated and called as such:
     * CBTInserter obj = new CBTInserter(root);
     * int param_1 = obj.insert(v);
     * TreeNode param_2 = obj.get_root();
     */
    
    /**
     * Definition for a binary tree node.
     * struct TreeNode {
     *   int val;
     *   TreeNode *left;
     *   TreeNode *right;
     *   TreeNode() : val(0), left(nullptr), right(nullptr) {}
     *   TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
     *   TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
     * };
     */
    class CBTInserter {
    public:
      vector<TreeNode*> tree;
    
      CBTInserter(TreeNode* root) {
        queue<TreeNode*> q{{root}};
        while (!q.empty()) {
          auto node = q.front();
          q.pop();
          tree.push_back(node);
          if (node->left) q.push(node->left);
          if (node->right) q.push(node->right);
        }
      }
    
      int insert(int v) {
        int pid = tree.size() - 1 >> 1;
        TreeNode* node = new TreeNode(v);
        tree.push_back(node);
        TreeNode* p = tree[pid];
        if (!p->left)
          p->left = node;
        else
          p->right = node;
        return p->val;
      }
    
      TreeNode* get_root() {
        return tree[0];
      }
    };
    
    /**
     * Your CBTInserter object will be instantiated and called as such:
     * CBTInserter* obj = new CBTInserter(root);
     * int param_1 = obj->insert(v);
     * TreeNode* param_2 = obj->get_root();
     */
    
    /**
     * Definition for a binary tree node.
     * type TreeNode struct {
     *   Val int
     *   Left *TreeNode
     *   Right *TreeNode
     * }
     */
    type CBTInserter struct {
      tree []*TreeNode
    }
    
    func Constructor(root *TreeNode) CBTInserter {
      q := []*TreeNode{root}
      tree := []*TreeNode{}
      for len(q) > 0 {
        node := q[0]
        tree = append(tree, node)
        q = q[1:]
        if node.Left != nil {
          q = append(q, node.Left)
        }
        if node.Right != nil {
          q = append(q, node.Right)
        }
      }
      return CBTInserter{tree}
    }
    
    func (this *CBTInserter) Insert(v int) int {
      pid := (len(this.tree) - 1) >> 1
      node := &TreeNode{Val: v}
      this.tree = append(this.tree, node)
      p := this.tree[pid]
      if p.Left == nil {
        p.Left = node
      } else {
        p.Right = node
      }
      return p.Val
    }
    
    func (this *CBTInserter) Get_root() *TreeNode {
      return this.tree[0]
    }
    
    /**
     * Your CBTInserter object will be instantiated and called as such:
     * obj := Constructor(root);
     * param_1 := obj.Insert(v);
     * param_2 := obj.Get_root();
     */
    
    /**
     * Definition for a binary tree node.
     * function TreeNode(val, left, right) {
     *   this.val = (val===undefined ? 0 : val)
     *   this.left = (left===undefined ? null : left)
     *   this.right = (right===undefined ? null : right)
     * }
     */
    /**
     * @param {TreeNode} root
     */
    var CBTInserter = function (root) {
      this.tree = [];
      const q = [root];
      while (q.length) {
        const node = q.shift();
        this.tree.push(node);
        if (node.left) {
          q.push(node.left);
        }
        if (node.right) {
          q.push(node.right);
        }
      }
    };
    
    /**
     * @param {number} v
     * @return {number}
     */
    CBTInserter.prototype.insert = function (v) {
      const pid = (this.tree.length - 1) >> 1;
      const node = new TreeNode(v);
      this.tree.push(node);
      const p = this.tree[pid];
      if (!p.left) {
        p.left = node;
      } else {
        p.right = node;
      }
      return p.val;
    };
    
    /**
     * @return {TreeNode}
     */
    CBTInserter.prototype.get_root = function () {
      return this.tree[0];
    };
    
    /**
     * Your CBTInserter object will be instantiated and called as such:
     * var obj = new CBTInserter(root)
     * var param_1 = obj.insert(v)
     * var param_2 = obj.get_root()
     */
    

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