Question

实现一个函数，n 秒后执行指定函数

function sleep(func, delay) {
  return new Promise((resolve, reject) => {
    setTimeout(() => {
      resolve(func())
    }, delay)
  })
}

function say(name) {
  console.log(name)
}
async function go() {
  await sleep(()=>say('nanjiu'),1000) //过一秒打印 nanjiu
  await sleep(()=>say('前端南玖'),2000) // 再过两秒打印前端南玖
}
go()