用pygame中的图像替换矩形

Question

我是Pygame和Python的新手。今天，我试图编码简化的上层运动。我做到了，它运行没有任何问题。但是无论如何我都有问题：“玩家”是一个矩形，但我希望他成为图像或类似的东西。有没有办法将RECT转换为图像？

哦，这是您需要的代码，我是从一个星期前提出的另一个问题（或更长的时间）提出的：

import pygame

pygame.init()

win = pygame.display.set_mode((700, 700))
pygame.display.set_caption("TopDown")
clock = pygame.time.Clock()

player = pygame.Rect(350, 350, 40, 60)
vel = 1

run = True
while run:
    clock.tick(50)

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False

    keys = pygame.key.get_pressed()
    player.x += (keys[pygame.K_d] - keys[pygame.K_a]) * vel
    player.y += (keys[pygame.K_s] - keys[pygame.K_w]) * vel
            
    win.fill((0, 0, 0))
    pygame.draw.rect(win, (255, 255, 255), player)
    pygame.display.update()

pygame.quit()

Answer 1

将图像加载 pygame.image.image.image.image.load（） 。此功能返回a pygame.surface.surface

player_image = pygame.image.load("player_image.png").convert_alpha()
player_rect = player_image.get_rect(center = (350, 350))

将 surface 放在显示屏上，“ nofollow noreferrer”> pygame.surface.blit ：

win.blit(player_image, player_rect)

---

最小示例：

import pygame
pygame.init()

win = pygame.display.set_mode((700, 700))
pygame.display.set_caption("TopDown")
clock = pygame.time.Clock()

player_image = pygame.image.load("player_image.png").convert_alpha()
player_rect = player_image.get_rect(center = (350, 350))
vel = 5

run = True
while run:
    clock.tick(50)

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False

    keys = pygame.key.get_pressed()
    player_rect.x += (keys[pygame.K_d] - keys[pygame.K_a]) * vel
    player_rect.y += (keys[pygame.K_s] - keys[pygame.K_w]) * vel
            
    win.fill((64, 238, 255))
    win.blit(player_image, player_rect)
    pygame.display.update()

pygame.quit()