即使我抓住了它，但抛出了例外

Question

我正在尝试列举收集URL，以使用。 当轨道ID不存在时，即使我正在捕获所述的确切错误，该程序也会引发错误。该错误说在处理异常时，发生了另一个例外，这是否意味着我设置了我的尝试不正确？

import spotipy
from spotipy.oauth2 import SpotifyOAuth

sp = spotipy.Spotify(auth_manager=SpotifyOAuth(client_id="...",
                                               client_secret="...",
                                               redirect_uri="http://localhost/",
                                               scope="playlist-modify-public",
                                               requests_timeout=5))
try:
    track = sp.track('7IaxPh0ttHTsJ4rVPPiQ9V', 'NL')
except sp.SpotifyException:
    x = 0

这是我收到的错误消息：

Exception has occurred: SpotifyException
http status: 404, code:-1 - https://api.spotify.com/v1/tracks/7IaxPh0ttHTsJ4rVPPiQ9V?market=NL:
 Non existing id: 'spotify:track:7IaxPh0ttHTsJ4rVPPiQ9V', reason: None

During handling of the above exception, another exception occurred:

  File "C:\Users\Dirkv\OneDrive\Documents\Projects\SelfStudy\Python\Music Bot\music_bot.py", line 38, in <module>
    track = sp.track(url, 'NL')

Answer 1

您需要从 spotipy 导入错误，而不是 sp

import spotipy
from spotipy.oauth2 import SpotifyOAuth

sp = spotipy.Spotify(auth_manager=SpotifyOAuth(client_id="...",
                                               client_secret="...",
                                               redirect_uri="http://localhost/",
                                               scope="playlist-modify-public",
                                               requests_timeout=5))

try:
    track = sp.track('7IaxPh0ttHTsJ4rVPPiQ9V', 'NL')
except spotipy.SpotifyException :
    x = 0
except spotipy.SpotifyOauthError:
    print("SpotifyOauthError")

注意：

请勿发布您的 client_id 或 client_secret 为了您自己的安全