如何在Java中实现这个REST get方法？

发布于 2024-12-09 03:01:05 字数 1262 浏览 0 评论 0原文

我有以下成功运行的 REST get 请求：

在此处输入图像描述

结果是一个 XML 文档，然后我想要解析。我在Java中尝试了同样的操作：

我使用以下代码：

public void getRootService() throws ClientProtocolException, IOException {

    HttpGet httpGet = new HttpGet("https://localhost:9443/ccm/rootservices");
    httpGet.setHeader("Accept", "text/xml");
    HttpResponse response = client.execute(httpGet);
    HttpEntity entity = response.getEntity();
    InputStream in = entity.getContent();
    String projectURL = XMLDocumentParser.parseDocument(in);

    System.out.println(projectURL);
    HttpGet getProjectsRequest = new HttpGet("https://localhost:9443/ccm/process/project-areas");
    getProjectsRequest.setHeader("Content-Type", "application/xml;charset=UTF-8");
    getProjectsRequest.setHeader("Accept-Charset", "UTF-8");
    getProjectsRequest.setHeader("Accept", "application/xml");


    ResponseHandler<String> handler = new BasicResponseHandler();
    String projectResponse = client.execute(getProjectsRequest, handler);
    //String projectResponse = client.execute(getProjectsRequest, handler);

    System.out.println(projectResponse);

}

但是我该如何进行身份验证？我尝试为值“Authorization”添加另一个标头字段，但没有得到相同的结果。

原文

I have the following REST get Request that works successfully:

enter image description here

The result is a XML document that I then want to parse. I tried the same in Java:

I use the following code:

public void getRootService() throws ClientProtocolException, IOException {

    HttpGet httpGet = new HttpGet("https://localhost:9443/ccm/rootservices");
    httpGet.setHeader("Accept", "text/xml");
    HttpResponse response = client.execute(httpGet);
    HttpEntity entity = response.getEntity();
    InputStream in = entity.getContent();
    String projectURL = XMLDocumentParser.parseDocument(in);

    System.out.println(projectURL);
    HttpGet getProjectsRequest = new HttpGet("https://localhost:9443/ccm/process/project-areas");
    getProjectsRequest.setHeader("Content-Type", "application/xml;charset=UTF-8");
    getProjectsRequest.setHeader("Accept-Charset", "UTF-8");
    getProjectsRequest.setHeader("Accept", "application/xml");


    ResponseHandler<String> handler = new BasicResponseHandler();
    String projectResponse = client.execute(getProjectsRequest, handler);
    //String projectResponse = client.execute(getProjectsRequest, handler);

    System.out.println(projectResponse);

}

But how can I do the authentication? I tried to just add another header field for the value "Authorization" but then I don't get the same result.

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橘虞初梦 2024-12-16 03:01:05

我认为你必须创建一个UsernamePasswordCredentials，类似于（未经测试）的东西；

CredentialsProvider credsProvider = new BasicCredentialsProvider();
credsProvider.setCredentials(
    new AuthScope("somehost", AuthScope.ANY_PORT), 
    new UsernamePasswordCredentials("username", "password"));

HttpClient httpclient = new DefaultHttpClient();
httpclient.setCredentialsProvider(credsProvider);

请参阅 http://hc.apache.org/httpcomponents-client- ga/tutorial/html/authentication.html

编辑：
刚刚尝试了以下代码，并在我们受 BASIC 保护的开发环境中成功调用了 REST 服务。

public static void main(String[] args) throws ClientProtocolException, IOException {
    CredentialsProvider credsProvider = new BasicCredentialsProvider();
    credsProvider.setCredentials(
        new AuthScope("dev.*******.com", AuthScope.ANY_PORT), 
        new UsernamePasswordCredentials("*****", "******"));


    DefaultHttpClient client = new DefaultHttpClient();
    client.setCredentialsProvider(credsProvider);

    String url = "http://dev.******.com:18081/path/to/service/id.xml";

    HttpGet get = new HttpGet(url);
    ResponseHandler<String> handler = new BasicResponseHandler();
    String resp = client.execute(get, handler);

    System.out.println(resp);
  }

I think you have to create a UsernamePasswordCredentials, something along the lines of (untested);

CredentialsProvider credsProvider = new BasicCredentialsProvider();
credsProvider.setCredentials(
    new AuthScope("somehost", AuthScope.ANY_PORT), 
    new UsernamePasswordCredentials("username", "password"));

HttpClient httpclient = new DefaultHttpClient();
httpclient.setCredentialsProvider(credsProvider);

See http://hc.apache.org/httpcomponents-client-ga/tutorial/html/authentication.html

Edit:
Just tried the following code and successfully called a REST service on our dev environment that is BASIC protected.

public static void main(String[] args) throws ClientProtocolException, IOException {
    CredentialsProvider credsProvider = new BasicCredentialsProvider();
    credsProvider.setCredentials(
        new AuthScope("dev.*******.com", AuthScope.ANY_PORT), 
        new UsernamePasswordCredentials("*****", "******"));


    DefaultHttpClient client = new DefaultHttpClient();
    client.setCredentialsProvider(credsProvider);

    String url = "http://dev.******.com:18081/path/to/service/id.xml";

    HttpGet get = new HttpGet(url);
    ResponseHandler<String> handler = new BasicResponseHandler();
    String resp = client.execute(get, handler);

    System.out.println(resp);
  }

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忆伤 2024-12-16 03:01:05

您可以将 Authorization 标头显式添加到 HttpRequestBase（HttpGet、HttpPost 等的抽象类）

此示例显示基本授权值是如何产生的。

String unhashedString = userName + ":" + password;
String hashedString = Base64.encode(unhashedString); //This class doesn't exist, it's for demonstration purpose only.

HttpGet.setHeader("Authorization", "Basic " + hashedString);

在服务器中，您将必须执行相反的操作（如果您正在执行自己的实现。

You can explicitly add Authorization header to HttpRequestBase (an abstract class for HttpGet, HttpPost, etc.)

This example shows how Basic Authorization value is made.

String unhashedString = userName + ":" + password;
String hashedString = Base64.encode(unhashedString); //This class doesn't exist, it's for demonstration purpose only.

HttpGet.setHeader("Authorization", "Basic " + hashedString);

In the server, you will have to do the reverse (if you're doing your own implementation.

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