将数组合并到没有键的数组？

发布于 2024-11-16 16:22:42 字数 508 浏览 0 评论 0原文

我正在尝试让 Facebook 上传带有随机标签朋友的照片。程序运行正确，但我在数组上得到了堆栈

$args = array(  
    'message' => 'Test Tags Text',  
    "access_token" => $access_token,  
    "image" => $files,
    'tags'    => $id,
);

$id 是数组好友列表，格式如下

$friends = $facebook->api('/me/friends'); 
$frand = array_rand( $friends['data'], 20 );

foreach($frand as $fid){ 
    $id[$fid]['tag_uid'] =  $friends['data'][$fid]['id'];
$id[$fid]['x']  = 0;
$id[$fid]['y']  = 0;
}

原文

im trying to make facebook upload photo with random tag friend.
the program was run correctly but i got stack on the array

$args = array(  
    'message' => 'Test Tags Text',  
    "access_token" => $access_token,  
    "image" => $files,
    'tags'    => $id,
);

the $id is array friend list here the format

$friends = $facebook->api('/me/friends'); 
$frand = array_rand( $friends['data'], 20 );

foreach($frand as $fid){ 
    $id[$fid]['tag_uid'] =  $friends['data'][$fid]['id'];
$id[$fid]['x']  = 0;
$id[$fid]['y']  = 0;
}

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流心雨 2024-11-23 16:22:42

更新2：

请阅读有关数组的内容：PHP 手册数组< /a>.即使您没有指定，数组中的每个元素都有一个键。数组中不能有没有键的元素。

定义数组（无需指定键）和打印数组（为您提供数组的文本表示形式）之间存在差异。

更新： 所以看来它必须是

$args['tags'] = $id;

$id 已经是一个数组了。如果将其传递给 array，它将创建一个以 $id 作为第一个元素的新数组。

旧答案：

您已经在谈论合并。您看过array_merge^[文档]？

$args['tags'] = array_merge($args['tags'], $id);

当然， $args['tags'] = array( $id ); 不起作用。它

覆盖 $args['tags'] 已有的值。
正如您已经注意到的，它将已经是数组的 $id 添加到数组中。如果 $args['tags'] 没有值，您只需执行 $args['tags'] = $id; 即可。

Update 2:

Please read about arrays: PHP manual arrays. Every element in an array has a key even if you don't specify it. You cannot have an element in an array without key.

There is a difference between defining an array, where you don't have to specify keys, and printing the array, which gives you a textual representation of the array.

Update: So it seems it has to be

$args['tags'] = $id;

$id is already an array. If you pass it to array, it will create a new array with the $id as first element.

Old answer:

You are already talking about merge. Have you had a look at array_merge^[docs]?

$args['tags'] = array_merge($args['tags'], $id);

Of course, $args['tags'] = array( $id ); does not work. It

Overwrites the already existing value of $args['tags'].
As you already noticed, it adds $id which is already an array, to an array. If $args['tags'] does not have a value, you could just do $args['tags'] = $id;.

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小矜持 2024-11-23 16:22:42

我建议使用compact($example1,$example2,$example3)，但结果将与您可能习惯的数组合并不同：

$example1 = array (x,y,z);
$example2 = array (a,b,c);
$example3 = array (d,e,f);

$mergedValue = compact('example1','example2','example3');
var_dump ($mergedValue);

// output will be:
array(3) { ["example1"]=> array(3) { [0]=> string(1) "x" [1]=> string(1) "y" [2]=> string(1) "z" } ["example2"]=> array(3) { [0]=> string(1) "a" [1]=> string(1) "b" [2]=> string(1) "c" } ["example3"]=> array(3) { [0]=> string(1) "d" [1]=> string(1) "e" [2]=> string(1) "f" } }

涵盖compact的php手册的链接是：

http://php.net/manual/en/function.compact.php

I would suggest using compact($example1,$example2,$example3), but the result will be different than what you might be used to with array merge:

$example1 = array (x,y,z);
$example2 = array (a,b,c);
$example3 = array (d,e,f);

$mergedValue = compact('example1','example2','example3');
var_dump ($mergedValue);

// output will be:
array(3) { ["example1"]=> array(3) { [0]=> string(1) "x" [1]=> string(1) "y" [2]=> string(1) "z" } ["example2"]=> array(3) { [0]=> string(1) "a" [1]=> string(1) "b" [2]=> string(1) "c" } ["example3"]=> array(3) { [0]=> string(1) "d" [1]=> string(1) "e" [2]=> string(1) "f" } }

The link to php manual where compact is covered is:

http://php.net/manual/en/function.compact.php

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